Suppose that a^2 varies inversely with b^3. If a = 7 when b = 4, find the value of a^2 when b = 6.
Since a2 varies inversely with b3: a2 = k / b3.
a = 7, b = 4: 72 = k / 43 ---> 49 = k / 64 ---> k = 49 / 64
So, the equation is: a2 = 49 / (64 · b3)
When b = 6: a2 = 49 / (64 · 63) ---> a2 = ....
