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Suppose that a^2 varies inversely with b^3. If a = 7 when b = 4, find the value of a^2 when b = 6.

 Feb 17, 2022
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Since  a2  varies inversely with  b3:  a2  =  k / b3.

 

a = 7, b = 4:  72  =  k / 43   --->   49  =  k / 64   --->   k  =  49 / 64

 

So, the equation is:  a2  =  49 / (64 · b3)

 

When  b = 6:  a2  =  49 / (64 · 63)  --->   a2  =  ....

 Feb 18, 2022

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