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Y varies directly as x and inversely as the square of z, and when x = 32, y = 6 and z = 4. Find x when y = 3 and z = 10. 

 Apr 15, 2022
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y =  k x / z^2

 

6 = k (32)  / (4)^2

 

6 = (32/16)k

 

6 = 2k

 

k = 3  = variation constant

 

So......

 

3 = 3 x / (10)^2

 

1 =  x / 10^2

 

x = 10^2   =  100

 

 

 

cool cool cool

 Apr 15, 2022

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