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Suppose that a^2 varies inversely with b^3. If a=3 when b=7 find the value of a^2 when b=6.

 Jun 6, 2022
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a^2  = k / b^3       where k  is the proportionality constant

 

3^2  = k / (7)^3

 

k =  3^2  / 7^3  =   9 / 343   

 

So

 

a^2  = (9/343) / 6^3  =  9 / [343 * 6^3 ] =  9 / 74088  =  1/ 8232

 

 

cool cool cool

 Jun 6, 2022

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