prove ..

$$\frac{1}{\sqrt2}\\\\ =\frac{1\times \sqrt2}{\sqrt2\times \sqrt2}\\\\ =\frac{\sqrt2}{2}\\\\\\ or\;alternatively\\\\ \frac{\sqrt2}{2}\\\\ =\frac{\sqrt2\div \sqrt2}{2\div \sqrt2}\\\\ =\frac{1}{2^1\div 2^{1/2}}\\\\ =\frac{1}{2^{1-(1/2)}}\\\\ =\frac{1}{2^{(1/2)}}\\\\ =\frac{1}{\sqrt2 }\\\\$$

melody !! You are gorgeous 

Thanks,

Flattery goes a long way with me