prove the following using trigonometry thanks!
\(-\sqrt{3}<\frac{\sqrt3x+1}{\sqrt{x^2+1}}\leq 2\)
\(1) \text{divide all terms by }2\\ 2) \text{consider a right triangle with legs }s_1 = \dfrac{\sqrt{3}}{2}x,~s_2 = \dfrac 1 2 x\)
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