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prove the following using trigonometry thanks! 

\(-\sqrt{3}<\frac{\sqrt3x+1}{\sqrt{x^2+1}}\leq 2\)

 Apr 6, 2019
 #1
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\(1) \text{divide all terms by }2\\ 2) \text{consider a right triangle with legs }s_1 = \dfrac{\sqrt{3}}{2}x,~s_2 = \dfrac 1 2 x\)

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 Apr 6, 2019

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