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Prove the Identity.

2tantheta/1+tan^2theta= sin2theta

 Dec 8, 2016
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2tan θ / [1+ tan^2 θ] = sin2θ

 

[2 sinθ/cosθ] / [ sec^2 θ ]  = sin 2θ

 

[2 sinθ/cosθ] /  [1 /cos^2 θ ]   = sin 2θ

 

[2 sinθ/cosθ] * cos^2 θ  = sin 2θ

 

2sinθcosθ  = sin2θ

 

 

cool cool cool

 Dec 8, 2016

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