Prove the Identity.
2tantheta/1+tan^2theta= sin2theta
2tan θ / [1+ tan^2 θ] = sin2θ
[2 sinθ/cosθ] / [ sec^2 θ ] = sin 2θ
[2 sinθ/cosθ] / [1 /cos^2 θ ] = sin 2θ
[2 sinθ/cosθ] * cos^2 θ = sin 2θ
2sinθcosθ = sin2θ