Show that the midpoint of the segment connecting \(z_1 \)and \(z_2\) on the complex plane is \((z_1+z_2)/2\).
+118609 I m not sure what I am meant to do to show this.
To me it is just obvious. 
Anyway ......if you let
\(z_1=a(cos\theta +isin\theta )\\ z_2=a(cos\alpha +isin\alpha )\\ \text{midpoint will be average of the real parts + average of the imaginary part}\\ midpoint=\frac{a(cos\theta +\cos\alpha)}{2}+\frac{a(sin\theta +\sin\alpha)}{2}\\ midpoint=\frac{a(cos\theta +\cos\alpha)+a(sin\theta +\sin\alpha)}{2}\\ midpoint=\frac{z_1+z_2}{2}\\\)
