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avatar+893 

Answer: 1806

 

What I did:

 

 Jul 30, 2019
 #1
avatar+103148 
+2

 

 

This is analogous to the situation of  distributing 7 distinct balls into 3 distinct boxes such that every box  must contain at least one ball

 

The total arrangements are given by :

 

(Stirling number of the second kind) (7, 3)  * 3!  =

 

S2 (7,3) * 3!  =

 

301  * 3!  =

 

301 * 6  =

 

1806

 

cool cool cool

 Jul 30, 2019
 #2
avatar+893 
+1

Thanks for the help, CPhill!!!

dgfgrafgdfge111  Jul 30, 2019

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