+0  
 
+1
207
1
avatar+929 

Please help

 Jun 28, 2019
 #1
avatar+6046 
+1

All sequences must end with {3rd 0, 1,1,1,1}

Clearly we must start with 0.

 

We can form

 

0001111

 

010101111

 

00101111

 

001101111

 

and that's it.

 

The probabilities of flipping these sequences is

 

\(\dfrac{1}{128}+\dfrac{1}{256}+\dfrac{2}{512}=\dfrac{1}{64}\)

.
 Jun 29, 2019

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