+0

# puzzel

+5
473
6
+18

calculation the number below to get as close as possible to target number

target number 150

5,6,4,12,19

you can use any mathmatical operation but each number only once

Archy  Nov 24, 2014

#6
+394
+16

(19 - 4) * 6 + 12 * 5 = 150

(19 - 4) * 12 - 6 * 5 = 150

Heureka, your maths are always amazing.

This simple problem demonstrates just how amazing!

_7UP_

SevenUP  Nov 24, 2014
#1
+676
+11

$$\left({\mathtt{19}}{\mathtt{\,\times\,}}{\mathtt{5}}\right){\mathtt{\,\small\textbf+\,}}\left({\mathtt{4}}{\mathtt{\,\times\,}}{\mathtt{12}}\right){\mathtt{\,\small\textbf+\,}}{\mathtt{6}} = {\mathtt{149}}$$

TakahiroMaeda  Nov 24, 2014
#2
+93683
+8

Thanks Archy - I like people putting up puzzles

Thanks for playing TakakiroMaeda

6(19+4)+12=150

Melody  Nov 24, 2014
#3
+27056
+16

$${\frac{\left({\mathtt{19}}{\mathtt{\,-\,}}{\mathtt{4}}\right){\mathtt{\,\times\,}}{\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{12}}}{{\mathtt{6}}}} = {\mathtt{150}}$$

.

Alan  Nov 24, 2014
#4
+7188
+3

$${\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{6}}{\mathtt{\,\times\,}}{\mathtt{4}}{\mathtt{\,\small\textbf+\,}}{\mathtt{19}}{\mathtt{\,\small\textbf+\,}}{\mathtt{12}} = {\mathtt{151}}$$

Now we have one less, one more, and one right on

happy7  Nov 24, 2014
#5
+20025
+16

target number 150

5,6,4,12,19

$$150 = 12 *( 19 - 5 - \dfrac{6}{4} )$$

$$150 = 6+ 4*(5+12+19)$$

heureka  Nov 24, 2014
#6
+394
+16

(19 - 4) * 6 + 12 * 5 = 150

(19 - 4) * 12 - 6 * 5 = 150

Heureka, your maths are always amazing.

This simple problem demonstrates just how amazing!

_7UP_

SevenUP  Nov 24, 2014