Here is a pyramid with a square base ABCD. AB = 6 m.
The vertex T is 12 m vertically above M, the midpoint of AC. Calculate the size of angle TAC.
The diagonal AC = sqrt 72 so AM = 1/2 sqrt 72
tan TAC = opp/adj = 12 /(1/2 sqrt 72)
TAC = arctan (12/(1/2 sqrt72) = 70.53 degrees