A regular tetrahedron is a pyramid with four faces, each of which is an equilateral triangle.
Let $V$ be the volume of a regular tetrahedron whose sides each have length $1$. What is the exact value of $V^2$ ?
The volume of a regualr tetrahedron with edge length " a " is given by
a^3 / √72
So...the volume of the tetrahedron is
1^3 /√72 =
1 / √72 [units^3]
So
V^2 = 1 /72
