Rectangle ABCD is the base of pyramid PABCD. If AB = 8, BC = 4, $PA \perp AD$, $PA \perp AB$, and PB = 19, then what is the volume of PABCD?
I believe that we have an oblique pyramid
Area of base = 8 * 4 = 32
Height = sqrt (PB^2 - AB^2 ] = sqrt [ 19^2 - 8^2] = sqrt (297)
Volume = (1/3) base * height= (1/3) (32)sqrt (297) ≈ 183.8 units^3
