Pythagoras von 20 *20 meter

Question

Pythagoras von 20 *20 meter

0

702

1

Pythagoras von 20 *20 meter

Guest Jun 14, 2015

Best Answer

1⁺⁰ Answers

#1

+14538

+5

Best Answer

a = 20 m ; b = 20 m

c² = a² + b² ; c = ${\sqrt{{{\mathtt{a}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{b}}}^{{\mathtt{2}}}}}$ ;

c = ${\sqrt{{{\mathtt{20}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{20}}}^{{\mathtt{2}}}}} = {\mathtt{28.284\: \!271\: \!247\: \!461\: \!901}}$

radix Jun 14, 2015

2 Online Users

radix · Answer 1 · 2015-06-14T03:52:00

a = 20 m ; b = 20 m

c² = a² + b² ; c = ${\sqrt{{{\mathtt{a}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{b}}}^{{\mathtt{2}}}}}$ ;

c = ${\sqrt{{{\mathtt{20}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{20}}}^{{\mathtt{2}}}}} = {\mathtt{28.284\: \!271\: \!247\: \!461\: \!901}}$

Pythagoras von 20 *20 meter

0 users composing answers..

Best Answer

a = 20 m ; b = 20 m

c² = a² + b² ; c = ${\sqrt{{{\mathtt{a}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{b}}}^{{\mathtt{2}}}}}$ ;

c = ${\sqrt{{{\mathtt{20}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{20}}}^{{\mathtt{2}}}}} = {\mathtt{28.284\: \!271\: \!247\: \!461\: \!901}}$

1⁺⁰ Answers

a = 20 m ; b = 20 m

c² = a² + b² ; c = ${\sqrt{{{\mathtt{a}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{b}}}^{{\mathtt{2}}}}}$ ;

c = ${\sqrt{{{\mathtt{20}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{20}}}^{{\mathtt{2}}}}} = {\mathtt{28.284\: \!271\: \!247\: \!461\: \!901}}$

2 Online Users

Top Users

Sticky Topics

Pythagoras von 20 *20 meter

0 users composing answers..

Best Answer

a = 20 m ; b = 20 m

c² = a² + b² ; c =√a2+b2{\sqrt{{{\mathtt{a}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{b}}}^{{\mathtt{2}}}}} ;

c = √202+202=28.284271247461901{\sqrt{{{\mathtt{20}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{20}}}^{{\mathtt{2}}}}} = {\mathtt{28.284\: \!271\: \!247\: \!461\: \!901}}

1+0 Answers

a = 20 m ; b = 20 m

c² = a² + b² ; c =√a2+b2{\sqrt{{{\mathtt{a}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{b}}}^{{\mathtt{2}}}}} ;

c = √202+202=28.284271247461901{\sqrt{{{\mathtt{20}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{20}}}^{{\mathtt{2}}}}} = {\mathtt{28.284\: \!271\: \!247\: \!461\: \!901}}

2 Online Users

Top Users

Sticky Topics

c² = a² + b² ; c = ${\sqrt{{{\mathtt{a}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{b}}}^{{\mathtt{2}}}}}$ ;

c = ${\sqrt{{{\mathtt{20}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{20}}}^{{\mathtt{2}}}}} = {\mathtt{28.284\: \!271\: \!247\: \!461\: \!901}}$

1⁺⁰ Answers

c² = a² + b² ; c = ${\sqrt{{{\mathtt{a}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{b}}}^{{\mathtt{2}}}}}$ ;

c = ${\sqrt{{{\mathtt{20}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{20}}}^{{\mathtt{2}}}}} = {\mathtt{28.284\: \!271\: \!247\: \!461\: \!901}}$