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Pythagoras von 20 *20 meter

 Jun 14, 2015

Best Answer 

 #1
avatar+14538 
+5

a = 20 m     ;   b = 20 m

 

c² = a² + b²      ;   c =$${\sqrt{{{\mathtt{a}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{b}}}^{{\mathtt{2}}}}}$$     ; 

 

  c =  $${\sqrt{{{\mathtt{20}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{20}}}^{{\mathtt{2}}}}} = {\mathtt{28.284\: \!271\: \!247\: \!461\: \!901}}$$

 Jun 14, 2015
 #1
avatar+14538 
+5
Best Answer

a = 20 m     ;   b = 20 m

 

c² = a² + b²      ;   c =$${\sqrt{{{\mathtt{a}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{b}}}^{{\mathtt{2}}}}}$$     ; 

 

  c =  $${\sqrt{{{\mathtt{20}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{20}}}^{{\mathtt{2}}}}} = {\mathtt{28.284\: \!271\: \!247\: \!461\: \!901}}$$

radix Jun 14, 2015

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