What is the perimeter of a right triangle with a 34 inch hypotenuse and a 1 foot leg? Write your answer in inches in simplest form.
+592 1 foot = 12 inches.
This means the other leg is: \(\sqrt{34^2-12^2} = \sqrt{1012} = 2\sqrt{253}\)
Which means the perimeter of this triangle is
\(2\sqrt{253} + 12 + 34 = 46 + 2\sqrt{253} ≈ 77.81\)
So your answer is 46 + 2√253 inches, or aboutt 77.81 inches
+592 1 foot = 12 inches.
This means the other leg is: \(\sqrt{34^2-12^2} = \sqrt{1012} = 2\sqrt{253}\)
Which means the perimeter of this triangle is
\(2\sqrt{253} + 12 + 34 = 46 + 2\sqrt{253} ≈ 77.81\)
So your answer is 46 + 2√253 inches, or aboutt 77.81 inches
