In a certain right triangle, the hypotenuse equals (x+z) while the other two sides are (x+y) and (y+z) for positive integers x, y, z. If y+4=z and z>x , then compute z/x.
We see that z=y+4
using Pythagorean theorem, we find that (x+y)^2+(y+z)^2=(x+z)^2,
plugging in the equation for 2 variables, we get
(x+y)^2+(2y+4)^2=(x+y+4)^2
if we simplify the above equation of two variables, then you should get
y^2+2y=2x
now use some trial and error on y and see if x and z will satisfy, hint: there is only one solution
