What is the length of CB? Round your answer to the nearest hundredths place.
we can use the Pythagorean theorem.
\(AB^2 = AC^2+CB^2\)
= \(21^2 = 14^2 + CB^2\)
= \(441 = 196 + CB^2\)
= \(245 = CB^2\)
= \(CB = \sqrt{245}\)
~ \(15.65\)
hope this helped! please let me know if you are still confused
