Find the value of x to the nearest tenth.
Note that we can find the hyppotenuse^2 of the triangle on the right as
8^2 + 4^2 = h^2
64 + 16 = h^2 = 80
So...on the left....x is the hypotenusr of that triangle so
h^2 + 7^2 =x^2
80 + 49 = x^2
129 = x^2
sqrt (129) = x
