Belmont is 7 miles due north of the airport, and Newton is 6 miles due east of the airport. How far apart are Belmont and Newton? If necessary, round to the nearest tenth.
+106 Oh, this looks like a pythag problem, to better understand pythag go to:
https://en.wikipedia.org/wiki/Pythagorean_theorem
So, we have Belmont 7 miles north, and Newton 6 miles east:
So, our a is 7 and our b is 6
We have to fit the formula:
a^2 + b^2 = c^2
49 + 36 = c^2
85 = c^2
so the square root of 85 is
approximately 9.2
