A right triangle has an area of 24 sq in, and a height of 6". What is the hypotenuse's length?
The other leg has a length of 8", making the hypotenuse have a measurement of
\(d = \sqrt{{8}^{2}+{6}^{2}}\)
\(\sqrt{100} in.\)
or 10 in.
Area =[Base x Height] / 2
24 = B x 6/2
24 =B x 3
Base =24/3 =8 inches
Hypotenuse^2=8^2 + 6^2
H^2 = 64 + 36 =100 take the square root of both sides,
H = 10 inches.
Thank you so much. This helped alot!
