im not sure how to do this equation... find a third number so that the three numbers form a right triangle. the numbers are 9, 41, and blank, please help
Learn the standard pythagorean triples, they'll really come in handy.
You know, like 3-4-5 triangles.
One triple is 9-40-41- however in this case the 41 HAS to be the hypotenuse, because it is the largest number. If the triangle you are describing does not have a hypotenuse of 41, and 41 is the base or height, then you'll have to use the pythagorean theorem, a^2 + b^2 = c^2.
+10 If it is the hypotenuse that is missing, use the pythagorean theorem: a2 + b2 = c2
a=9
b=41
92 + 412 = c2
81+1681= c2
1762= c2
sqrt(1762)= c
Learn the standard pythagorean triples, they'll really come in handy.
You know, like 3-4-5 triangles.
One triple is 9-40-41- however in this case the 41 HAS to be the hypotenuse, because it is the largest number. If the triangle you are describing does not have a hypotenuse of 41, and 41 is the base or height, then you'll have to use the pythagorean theorem, a^2 + b^2 = c^2.
+26388 im not sure how to do this equation... find a third number so that the three numbers form a right triangle. the numbers are 9, 41, and blank, please help
\(\begin{array}{rcll} x^2+9^2 &=& 41^2 \quad & | \quad -9^2 \\ x^2 &=& 41^2 - 9^2 \\ x^2 &=& 1681 - 81 \\ x^2 &=& 1600 \quad & | \quad \sqrt{} \\ x &=& \sqrt{ 1600 } \\ x &=& 40 \\ \end{array}\)
The third number is 40.
