Q12.4.3). The sum of two numbers is 89. Three times the smaller number exceeds the larger number by 71. Find the numbers.
Let x be smaller number and y the larger...so...
x + y = 89 and
3x - 71 = y
Using the second equation to substitute for y in the first, we have
x + (3x -71) = 89 simplify
4x - 71 = 89 add 71 to both sides
4x = 160 divide by 4 on both sides
x = 40 so 40 + y = 89 subtract 40 from bth sides.....so......y = 49
Let x be smaller number and y the larger...so...
x + y = 89 and
3x - 71 = y
Using the second equation to substitute for y in the first, we have
x + (3x -71) = 89 simplify
4x - 71 = 89 add 71 to both sides
4x = 160 divide by 4 on both sides
x = 40 so 40 + y = 89 subtract 40 from bth sides.....so......y = 49