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A car driving over a suspension bridge is supported by a cable hanging between the ends of the bridge. Since its shape is a parabolic, it can be modeled by a quadratic equation. The height above the road bed of a bridge's cable h in inches measured at distance d in yards from the first tower is given by h=d^2-36d+324.

If the driver of a car looks out at a height of 49 inches above the road bed, at the distance(s) from the tower will the driver's eyes be at the same height as the cable?
 Mar 7, 2014
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snoopy1205:

A car driving over a suspension bridge is supported by a cable hanging between the ends of the bridge. Since its shape is a parabolic, it can be modeled by a quadratic equation. The height above the road bed of a bridge's cable h in inches measured at distance d in yards from the first tower is given by h=d^2-36d+324.

If the driver of a car looks out at a height of 49 inches above the road bed, at the distance(s) from the tower will the driver's eyes be at the same height as the cable?



Bridge.PNG

d 2-36d+324 = 49

d 2-36d+275=0

(d-11)*(d-25)=0

so there are two positions: d = 11 yards and d = 25 yards from any particular tower. Both are 11 yards from the nearest tower..

I guess we're in Lilliput!
 Mar 7, 2014

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