quadratic equation

Solve 6x = 2x^2 + 1

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$2x^2-6x+1=0$

a         b        c 

$x = {-b \pm \sqrt{b^2-4ac} \over 2a}$

$x = {-3 \pm \sqrt{9-4\cdot 2\cdot 1} \over 2\cdot 1}$

$x=\frac{1}{2}\cdot (-3\pm 1)$

$x_1=-1$

$x_2=-2$

  !

asinus made a small math mistake    b^2 = 36   not   9     ( b is 6    not 3)

using the Quadratic Formula as asinus showed the answer    x =  3/2 +-  sqrt(7) / 2