+14903
Solve 6x = 2x^2 + 1
Hello Guest!
\(2x^2-6x+1=0\)
a b c
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
\(x = {-3 \pm \sqrt{9-4\cdot 2\cdot 1} \over 2\cdot 1}\)
\(x=\frac{1}{2}\cdot (-3\pm 1)\)
\(x_1=-1\)
\(x_2=-2\)
!
+36915 asinus made a small math mistake b^2 = 36 not 9 ( b is 6 not 3)
using the Quadratic Formula as asinus showed the answer x = 3/2 +- sqrt(7) / 2
