Write the following equation in vertex form, find the vertex, find the y-intercept: y = x^2 + 6x - 16
Find the roots (x-intercepts).
+592 y = x2 + 6x - 16
y = x2 + 6x + 9 - 9 - 16
y = (x + 3)2 - 25
The vertex is (-3, -25)
The y intercept is when x is zero, which mean it's:
y = (0 + 3)2 - 25
y = 9 - 25
y = -16 (which is also just the "c" in the quadratic form)
(0, -16)
Finally, the x intercepts are:
0 = (x + 3)2 - 25
25 = (x + 3)2
± 5 = x + 3
x = 2 (2, 0)
x = -8 (-8, 0)
Hope this helps :)
+592 y = x2 + 6x - 16
y = x2 + 6x + 9 - 9 - 16
y = (x + 3)2 - 25
The vertex is (-3, -25)
The y intercept is when x is zero, which mean it's:
y = (0 + 3)2 - 25
y = 9 - 25
y = -16 (which is also just the "c" in the quadratic form)
(0, -16)
Finally, the x intercepts are:
0 = (x + 3)2 - 25
25 = (x + 3)2
± 5 = x + 3
x = 2 (2, 0)
x = -8 (-8, 0)
Hope this helps :)
