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Write the following equation in vertex form, find the vertex, find the y-intercept: y = x^2 + 6x - 16

 

Find the roots (x-intercepts).

 Mar 22, 2021

Best Answer 

 #1
avatar+544 
+1

y = x2 + 6x - 16 

y = x2 + 6x + 9 - 9 - 16 

y = (x + 3)2 - 25 

 

The vertex is (-3, -25)

The y intercept is when x is zero, which mean it's:
y = (0 + 3)2 - 25

y = 9 - 25

y = -16 (which is also just the "c" in the quadratic form)

(0, -16)

 

Finally, the x intercepts are: 

0 = (x + 3)2 - 25

25 = (x + 3)2

± 5 = x + 3

x = 2  (2, 0)

x = -8 (-8, 0)

 

Hope this helps :)

 Mar 22, 2021
 #1
avatar+544 
+1
Best Answer

y = x2 + 6x - 16 

y = x2 + 6x + 9 - 9 - 16 

y = (x + 3)2 - 25 

 

The vertex is (-3, -25)

The y intercept is when x is zero, which mean it's:
y = (0 + 3)2 - 25

y = 9 - 25

y = -16 (which is also just the "c" in the quadratic form)

(0, -16)

 

Finally, the x intercepts are: 

0 = (x + 3)2 - 25

25 = (x + 3)2

± 5 = x + 3

x = 2  (2, 0)

x = -8 (-8, 0)

 

Hope this helps :)

Logarhythm Mar 22, 2021

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