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How do I find the zero in this quadratic function? f(x)=-28x^2+67x-40
 May 18, 2016
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Solve for x:
-(28 x^2)+67 x-40 = 0

 

The left hand side factors into a product with three terms:
-((4 x-5) (7 x-8)) = 0

 

Multiply both sides by -1:
(4 x-5) (7 x-8) = 0

 

Split into two equations:
4 x-5 = 0 or 7 x-8 = 0

 

Add 5 to both sides:
4 x = 5 or 7 x-8 = 0

 

Divide both sides by 4:
x = 5/4 or 7 x-8 = 0

 

Add 8 to both sides:
x = 5/4 or 7 x = 8

 

Divide both sides by 7:
Answer: |  x = 5/4         or          x = 8/7

 May 18, 2016

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