Find the value of $k$ if the roots of the quadratic equation $7x^2 + 3x + k = 0$ are $\frac{-3 \pm 3 \sqrt{29}}{14}$.
\( \frac{-3 \pm 3 \sqrt{29}}{14} \)
The discriminant = 3^2 * 29 = 9*29 = 261
So
3^2 - 4 (7) (k) = 261
9 - 28k = 261
-28k = 252
k = -252 / 28 = -9