Can someone help me Solve using the quadratic forumla x^2+8x+7
Your equation 1 x^2 + 8x +7 =0 a = 1 b = 8 c = 7
Plug these values in to the quadratic formula to find values of x that satisfy the eqaution...
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
You should be able to do that.....
alternatively the expression is trivially factored as
(x+7)(x+1)=0
and you should be able to solve it by inspection from this form.