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A landscaper has enough cement to make a patio with an area of 150 square feet. The homeowner wants the length to be 6 feet longer than the width. What dimensions should be used for the patio? Round to the nearest tenth of a foot.
Guest Apr 11, 2012
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confusedmathguy:

patio with an area of 150 square feet



two equations:
l*w=150 (area formula length*width)
confusedmathguy:

length to be 6 feet longer than the width


l=6+w


[input]solve( l*w=150, l=6+w)[/input]
length=15.6
width=9.6

test:
[input]15.6feet*9.6feet in feet^2[/input]
admin  Apr 11, 2012

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