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Find a formula for the quadratic function whose graph has vertex (−2,−1) and y-intercept 5.

 Jan 25, 2021
edited by Guest  Jan 25, 2021

Best Answer 

 #1
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Vertex form     y = a (x+2)^2 -1     point given 0,5

                       5 = a(0+2)^2 -1    so a = 3/2

 

y = 3/2 (x+2)^2 -1               expand

y = 3/2 (x^2 +4x+4) - 1        simplify

         3/2 x^2 +6x+5

 Jan 25, 2021
 #1
avatar
+1
Best Answer

Vertex form     y = a (x+2)^2 -1     point given 0,5

                       5 = a(0+2)^2 -1    so a = 3/2

 

y = 3/2 (x+2)^2 -1               expand

y = 3/2 (x^2 +4x+4) - 1        simplify

         3/2 x^2 +6x+5

Guest Jan 25, 2021

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