What real value of $t$ produces the smallest value of the quadratic $t^2 -9t - 36 + 13t - 60$?
What real value of $t$ produces the smallest value of the quadratic $t^2 -9t - 36 + 13t - 60$?
t2 – 9t – 36 + 13t – 60
collect like terms t2 + 4t – 96
The lowest value will be the vertex, can be
found by setting the 1st derivitive to zero 2t + 4 = 0 ==>> t = – 2
At t = –2, the quadratic equals –100.
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