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-x2+4x-5(insert "less than or equal to" sign here)-2

Guest Mar 30, 2017
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-x^2 + 4x - 5 ≤  -2     add 2 to both sides

 

-x^2 + 4x -3 ≤  0       multiply through by - 1   and reverse the inequality sign

 

x^2 - 4x + 3 ≥ 0     factor

 

(x - 3) ( x - 1) ≥   0

 

Note  that  when   1  x < 3 ......the   inequality will be false

 

So  the solution  is   (-inf, 1}] U [3, inf )

 

 

 

cool cool cool

CPhill  Mar 30, 2017

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