Given a quadratic equation: x^2 - sqrt(5a^2 - 26a - 8) * x + (a^2 - 6a + 12) = 0
It has 2 integer roots. If a is an integer as well, what is the value of a?
I think you mean \(x^2-x\sqrt{5a^2-26a-8}+a^2-6a+12=0\)
Uhhhh......yah......that is what was posted ......
