Let $a$ and $b$ be the roots of $x^2 + 7x - 4 = -x^2 + 9x + 6$. Find $(a + 3) + (b + 3).$
Rewrite as
2x^2 -2x -10 = 0
We have the form mx^2 + nx + c
The sum of the roots a + b = -n / m = (- - 2) / 2 = 2/2 = 1
a + b = 1
(a + 3) + (b + 3) =
a + b + 6 =
1 + 6 =
7