The quadratic ax^2 + bx + c can be expressed in the form 2(x - 4)^2 + 8. When the quadratic 3ax^2 + 2bx + 3 is expressed in the form n(x - h)^2 + k, what is h?
+36915 2(x - 4)^2 + 8 expanded = 2x^2 -16x + 40 so a = 2 b = -16 c = 40
then 6x^2 -32x + 3 will become ( by completing the square for 'x' 6 ( x^2 - 16/3 x) + 3
6 ( x- 16/6)^2 - 167 2/3 <======== take it from here
