There exist constants a, h and k such that
x^2 + 12x + 4 = a(x - h)^2 + k
for all real numbers x. Enter the ordered triple (a,h,k).
x^2 + 12x + 4 complete the square on x
Take 1/2 of 12 = 6.....square it....=36 .... add and subtract it
x^2 + 12x + 36 + 4 - 36 factor the first three terms, simlify the rest
(x + 6)^2 - 32
(a, h, k) = ( 1, 6 , -32 )
