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The quadratic x^2 + bx + 16 = 0 has a double root.  Find all possible values of b.

 Feb 7, 2021
 #1
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The disciminat of the quadratic formula must = 0 for this to be true

b^2 - 4ac = 0   

b^2 - 4(1)16) = 0

b^2 = 64

b = +- 8

 Feb 7, 2021
 #2
avatar+118588 
+1

If this has a double root, then the discriminant = 0 ....so....

 

b^2   - 4(16)(1)  = 0

 

b^2   -  64  =   0

 

b^2  = 64      take  both square roots

 

b =  8        or  b  =   - 8

 

 

cool cool cool

 Feb 7, 2021

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