An apple is launched directly upward at 64 feet per second from a platform 80 feet high. The equation for this apple's height h at time t seconds after launch is h = -16t^2 + 64t + 80.

a. What is the height of the apple after 3 seconds?

b. Find the maximum height of the apple.

c. How many seconds will it take for the apple to reach the ground?

Guest Feb 15, 2021

#1**+1 **

a) put '3' in for 't' in the equation given and calculate the height at 3 sec

b.) max height will occur at t = -b/2a where b = 64 and a = -16

this is the TIME when the apple is at max height

to calculate THIS HEIGHT , put the t you just found into the equation and calculate max height

c) When the apple becomes applesauce, the height = 0

so solve 0 = -16t^{2} + 64 t + 80 use Quadratic Formula or factoring throw out any negative 't' value

ElectricPavlov Feb 15, 2021