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An apple is launched directly upward at 64 feet per second from a platform 80 feet high. The equation for this apple's height h at time t seconds after launch is h = -16t^2 + 64t + 80.

 

a. What is the height of the apple after 3 seconds?

 

b. Find the maximum height of the apple.

 

c. How many seconds will it take for the apple to reach the ground?

 Feb 15, 2021
 #1
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a)    put '3' in for 't'  in the equation given and calculate the height at 3 sec

b.)   max height will occur at t = -b/2a    where b = 64   and a = -16

          this is the TIME when the apple is at max height

              to calculate THIS HEIGHT , put the t you just found into the equation and calculate max height

c) When the apple becomes applesauce, the height = 0

         so   solve   0 = -16t2 + 64 t + 80         use Quadratic Formula or factoring       throw out any negative 't' value     

 Feb 15, 2021

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