An apple is launched directly upward at 64 feet per second from a platform 80 feet high. The equation for this apple's height h at time t seconds after launch is h = -16t^2 + 64t + 80.
a. What is the height of the apple after 3 seconds?
b. Find the maximum height of the apple.
c. How many seconds will it take for the apple to reach the ground?
+36916 a) put '3' in for 't' in the equation given and calculate the height at 3 sec
b.) max height will occur at t = -b/2a where b = 64 and a = -16
this is the TIME when the apple is at max height
to calculate THIS HEIGHT , put the t you just found into the equation and calculate max height
c) When the apple becomes applesauce, the height = 0
so solve 0 = -16t2 + 64 t + 80 use Quadratic Formula or factoring throw out any negative 't' value
