Find real numbers a, b, c such that 2x^2 - 8x + 2012 = a + b(x - 2) + c(x - 2)^2.
+36916 Expand to:
a + bx-2b+cx^2-4cx+4c the only coefficient of x^2 is c so c = 2
a + bx - 2b + 2x^2-8x+8 the 'x' coefficients have to add to -8 so b =0
a + 2x^2-8x+8 the constants have to add to 2012 so a = 2004
2x^2-8x+2012
+36916 Expand to:
a + bx-2b+cx^2-4cx+4c the only coefficient of x^2 is c so c = 2
a + bx - 2b + 2x^2-8x+8 the 'x' coefficients have to add to -8 so b =0
a + 2x^2-8x+8 the constants have to add to 2012 so a = 2004
2x^2-8x+2012
