What real value of produces the smallest value of the quadratic t^2 - 9t - 36 + t^2 - t + 4?
+14913 What real value produces the smallest value of the quadratic t^2 - 9t - 36 + t^2 - t + 4?
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\(f(t)=t^2 - 9t - 36 + t^2 - t + 4\\ f(t)=2t^2-10t-32\\ \frac{df(t)}{dt}=4t-10=0\)
\(t=2.5\)
The value t = 2.5 gives the smallest value of the square t ^ 2 - 9t - 36 + t ^ 2 - t + 4, namely - 44.5.
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