The equation y = -16t^2 + 80t describes the height (in feet) of a projectile launched from the ground at 80 feet per second. At what will the projectile reach 80 feet in height for the first time? Express your answer as a decimal rounded to the nearest tenth.
+36916 y = -16t^2 +80t
80 = -16 t^2 + 80t
-16t^2 +80t - 80 = 0 quadratic formula shows t = ~1.4 SECONDS
