The equation y = -16t^2 + 80t describes the height (in feet) of a projectile launched from the ground at 80 feet per second. At what will the projectile reach 80 feet in height for the first time? Express your answer as a decimal rounded to the nearest tenth.

Guest May 27, 2021

#1**+1 **

y = -16t^2 +80t

80 = -16 t^2 + 80t

-16t^2 +80t - 80 = 0 quadratic formula shows t = ~1.4 SECONDS

ElectricPavlov May 27, 2021