Let a and $b$ be the roots of the equation 2x^2 - 7x + 2 = 0.$ Find (a - 1) + (b - 1).
+2666 Note that \((a - 1) + (b - 1) = a + b - 2\)
From Vieta's, we know that \(a + b = -{b \over a} = {7 \over 2} \)
So, \((a - 1) + (b - 1) = {7 \over 2} - 2 = \color{brown}\boxed{1.5}\)
+128474 2x^2 - 7x + 2 = 0
sum of roots = 7/2 = 3.5
product of roots = 2/2 = 1
(a - 1) (b -1) = ab - (a+ b) + 1 = 1 - (3.5) + 1 = -1.5
+2666 Note that \((a - 1) + (b - 1) = a + b - 2\)
From Vieta's, we know that \(a + b = -{b \over a} = {7 \over 2} \)
So, \((a - 1) + (b - 1) = {7 \over 2} - 2 = \color{brown}\boxed{1.5}\)
