The equation y = -16t^2 + 60t describes the height (in feet) of a projectile launched from the ground at 60 feet per second upward. In how many seconds will the projectile first reach 44 feet in height? Express your answer as a decimal rounded to the nearest hundredth.

Guest Dec 1, 2022

#1**+2 **

44 feet in height is y value at 44. So 44 = -16t^2 + 60t will help you obtain the time.

16t^2 - 60t + 44 = 0

4t^2 - 15t + 11 = 0

(4t - 11)(t - 1) = 0

t = 1 and 2.75

If we are looking for the time where it reaches the height of 44 first, then we pick the smaller time, so the answer is **1 second**.

proyaop Dec 2, 2022