If s is a real number, then what is the smallest possible value of 2s^2-8s+19?
The minimum occurs at \(-{b \over 2a} = -{-8 \over 4} = 2\).
Now, substitute this into the equation: \(\text{___} = 2\times 2^2 - 8 \times 2 + 19\)
+2666 
