What real value of t produces the smallest value of the quadratic t^2 -9t - 36 + t^2 - 5t + 14?
t^2 -9t - 36 + t^2 - 5t + 14 simplify as
2t^2 - 14t - 22
The t that produces a min is the x coordinate of the vertex of this parabola given by
- (-14) / (2 * 2) = 14/4 = 7/2 = 3.5
