The quadratic x^2 + px + 4 has a minimum value of 3. What is p?
Max value will occur at - b/2a = - p/2
Put this into the equation to find the min value =3
(-p/2)2 + p (-p/2) + 4 = 3
p^2 /4 - p^2 /2 +1 = 0
- p^2 /4 + 1 = 0
-p^2 = -4
p = 2
+36916 
