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The quadratic x^2 + px + 4 has a minimum value of 3.  What is p?

 May 27, 2020
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Max value will occur at   - b/2a  = - p/2

 

Put this into the equation to find the min value =3

 

(-p/2)2 + p (-p/2) + 4 = 3

p^2 /4   - p^2 /2 +1 = 0

- p^2 /4 + 1 = 0

 

-p^2 = -4

p = 2   

 May 27, 2020

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