Find the roots of 8x^2 + 36x + 41 = 0.
8x2 + 36x + 41 = 0
a = 8 b = 36 c = 41
quadratic formula: x = [ -b +/- sqrt( b2 - 4·a·c ] / ( 2·a )
x = [ -36 +/- sqrt( 362 - 4·8·41 ] / ( 2·8 )
x = [ -36 +/- sqrt( - 16 ] / ( 16 )
x = -2.25 + 0.25i or -2.25 - 0.25i