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Suppose that a bottle rocket is launched upward with a initial velocity of 96ft/sec from a height of 880ft. Its height is h, in feet, after t seconds is given by h(t)=-16^2 + 96t + 880. After how long will the rocket reach the ground?

 Jun 11, 2022
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When it hits the ground,  the  height =   0    ......so......

 

 

-16t^2  + 96t  + 880  =  0      divide through by -16

 

t^2  - 6t  - 55  =  0

 

(t - 11) (t + 4) = 0

 

The first factor set =  0  gives us what we want

 

t - 11  = 0

 

t =  11   sec  to  hit the  ground

 

 

cool cool cool

 Jun 12, 2022

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