Suppose that a is a nonzero constant for which the equation ax^2 + 20x + 7 = 14x + 9 has only one solution. Find this solution.
+37157 ax^2 + 20x + 7 = 14x + 9 re-arrange
ax^2 + 6x -2 = 0 for only one solution ( one double root) the discriminant of the Quadratic Formula must = 0
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
b^2 - 4ac = 0
(6)^2 - 4 (a)(-2) = 0
8a = -36
a = -4.5
