+0  
 
0
28
1
avatar

Find the equation of a parabola whose vertex is at (−1, 7), whose axis of symmetry is x = −1, and whose y-intercept is (0, 20). Write your answer in vertex form.

 Jun 6, 2022
 #1
avatar+123413 
+1

We have  the form

 

y = a ( x - h)^2  + k

 

(h,k)   = the vertex =  ( -1, 7)   

 

So we have

 

y  = a( x  - -1)^2  + 7

 

y = a ( x + 1)^2  + 7

 

And the point (0,20) is on the graph so

 

20  = a ( 0 +1)^2 + 7

 

20 - 7  =   a * 1^2

 

13  = a

 

The equation is

 

y =  13 ( x + 1)^2  + 7

 

Here's a graph :  https://www.desmos.com/calculator/hnmgnpsmel

 

 

cool cool cool

 Jun 6, 2022

18 Online Users

avatar
avatar
avatar